Ta có :
\(4n+3⋮7n-2\)
Mà \(7n-2⋮7n-2\)
\(\Leftrightarrow\left\{{}\begin{matrix}27n+21⋮7n-2\\27n-8⋮7n-2\end{matrix}\right.\)
\(\Leftrightarrow29⋮7n-2\)
Vì \(n\in Z\Leftrightarrow7n-2\in Z;7n-2\inƯ\left(29\right)\)
\(\Leftrightarrow\left[{}\begin{matrix}7n-2=1\\7n-2=29\\7n-2=-1\\7n-2=-29\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}n=\dfrac{3}{7}\\n=\dfrac{31}{7}\\n=\dfrac{1}{7}\\n=\dfrac{-27}{7}\end{matrix}\right.\) (loại)
Vậy ko tìm dc n thỏa mãn

