Question

Tìm no đa thức x^3-2x^2+x

Answer 1

Ta có: \(x^3-2x^2+x=0\)

\(\Leftrightarrow x^3-x^2-x^2+x=0\)

\(\Leftrightarrow x\left(x^2-x\right)-\left(x^2-x\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(x^2-x\right)=0\)

\(\Leftrightarrow\left(x-1\right)x\left(x-1\right)=0\)

\(\Leftrightarrow x\left(x-1\right)^2=0\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\\left(x-1\right)^2=0\end{matrix}\right.\)\(\Leftrightarrow\)\(\left[{}\begin{matrix}x=0\\x-1=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)