Để hàm số xác định với mọi x
\(\Leftrightarrow\left(m+1\right)x^2+2mx+9m+5>0\) \(\forall x\)
\(\Leftrightarrow\left\{{}\begin{matrix}m+1>0\\\Delta'=m^2-\left(m+1\right)\left(9m+5\right)< 0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}m>-1\\-8m^2-14m-5< 0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}m>-1\\\left[{}\begin{matrix}m>-\frac{1}{2}\\m< -\frac{5}{4}\end{matrix}\right.\end{matrix}\right.\) \(\Rightarrow m>-\frac{1}{2}\)