\(\left\{{}\begin{matrix}-\frac{b}{2a}=\frac{3}{2}\\25a-5b-3=4\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}3a+b=0\\25a-5b=7\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}a=\frac{7}{40}\\b=-\frac{21}{40}\end{matrix}\right.\)
Hàm số có dạng: \(y=\frac{7}{40}x^2-\frac{21}{40}x-3\)