\(A=\left|x+1\right|-2\)
\(\left|x+1\right|\ge0\Rightarrow\left|x+1\right|-2\ge-2\)
Dấu "=" xảy ra khi:
\(x=-1\)
\(B=\left|x-1\right|+\left|3-x\right|\)
\(B\ge\left|x-1+3-x\right|\)
\(B\ge2\)
Dấu "=" xảy ra khi:
\(\left[{}\begin{matrix}\left\{{}\begin{matrix}x-1\ge0\Rightarrow x\ge1\\3-x\ge0\Rightarrow x\le3\end{matrix}\right.\\\left\{{}\begin{matrix}x-1< 0\Rightarrow x< 1\\3-x< 0\Rightarrow x>3\end{matrix}\right.\end{matrix}\right.\)
\(\Rightarrow1\le x\le3\)
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