\(\frac{2^7.3^6}{6^5.8^2}\)= \(\frac{2^7.3^6}{3^5.2^5.2^6}\)=\(\frac{2^7.3^6}{3^5.2^{11}}\)=\(\frac{3}{2^4}\)=\(\frac{3}{16}\)
đó là ý kiến của mình
\(a.\frac{2^7\times9^3}{6^5\times8^2}\)
\(=\frac{3}{16}\)
\(b.\frac{6^3+3\times6^2+3^3}{-13}\)
\(-\frac{333}{13}\)