Question

Tìm đạo hàm của các hàm số sau :

a) \(y=\dfrac{x-1}{5x-2}\)

b) \(y=\dfrac{2x+3}{7-3x}\)

c) \(y=\dfrac{x^2+2x+3}{3-4x}\)

d) \(y=\dfrac{x^2+7x+3}{x^2-3x}\)

Answer 1

a) = = .

b) = = .

c) = = .

d) y' =\(\dfrac{\left(x^2+7x+3\right)'\left(x^2-3x\right)-\left(x^2+7x+3\right)\left(x^2-3x\right)'}{\left(x^2-3x\right)^2}\)=\(\dfrac{\left(2x+7\right)\left(x^2-3x\right)-\left(x^2+7x+3\right)\left(2x-3\right)}{\left(x^2-3x\right)^2}\)=\(\dfrac{-2x^2-6x+9}{\left(x^2-3x\right)^2}\)