-x/3=24/4=6
=>x=-18
3/y2=6
=>y2=1/2
hay \(y=\pm\dfrac{\sqrt{2}}{2}\)
\(\dfrac{\left(z+3\right)^3}{-4}=6\)
=>(z+3)3=-24
\(\Leftrightarrow z+3=-\sqrt[3]{24}\)
hay \(z=-\sqrt[3]{24}-3\)
||t|-2|/8=6
=>||t|-2|=48
=>|t|-2=48
=>t=50 hoặc t=-50
-x/3=24/4=6
=>x=-18
3/y2=6
=>y2=1/2
hay \(y=\pm\dfrac{\sqrt{2}}{2}\)
\(\dfrac{\left(z+3\right)^3}{-4}=6\)
=>(z+3)3=-24
\(\Leftrightarrow z+3=-\sqrt[3]{24}\)
hay \(z=-\sqrt[3]{24}-3\)
||t|-2|/8=6
=>||t|-2|=48
=>|t|-2=48
=>t=50 hoặc t=-50
\(^{\dfrac{27}{4}}\)=\(\dfrac{-x}{3}\)=\(\dfrac{3}{y^2}\)=\(\dfrac{\left(z+3\right)^3}{-4}\)=\(\dfrac{\left|\left|t\right|-2\right|}{8}\)
Tìm x,y,z,t
Bài 1: Tìm x:
a) \(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
b) \(\left|\dfrac{5}{3}x\right|=\left|-\dfrac{1}{6}\right|\)
c) \(\left|\dfrac{3}{4}x-\dfrac{3}{4}\right|-\dfrac{3}{4}=\left|-\dfrac{3}{4}\right|\)
Bài 2: Tìm x,y:
a) \(\left|\dfrac{1}{2}-\dfrac{1}{3}+x\right|=\dfrac{1}{4}-\left|y\right|\)
b) \(\left|x-y\right|+\left|y+\dfrac{9}{25}\right|=0\)
Bài 3: Tìm giá trị nhỏ nhất:
a) A= \(\left|x+\dfrac{15}{19}\right|-1\)
b) B= \(\dfrac{1}{2}+\left|x-\dfrac{4}{7}\right|\)
Bài 4: Tìm giá trị lớn nhất:
a) A= 5- \(\left|\dfrac{5}{3}-x\right|\)
b) B= 9-\(\left|x-\dfrac{1}{10}\right|\)
\(Tìm\) \(x\)∈\(Z\)\(,\) \(biết\)\(:\)
\(a\)) \(\left(x-20\right)+\left(x-19\right)+\left(x-18\right)+...+99+100=100\)
\(b\)) \(213-x.\left(\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^{2020}}\right):\left(1-\dfrac{1}{2^{2020}}\right)=13\)
tìm x biết :
1.\(\dfrac{-5}{6}+\dfrac{8}{3}+\dfrac{-29}{6}\le x\le\dfrac{-1}{2}+2+\dfrac{5}{2}\)
2.\(\left(2,7x-1\dfrac{1}{2}x\right):\dfrac{2}{7}=\dfrac{-21}{4}\)
3.\(\left|2x-\dfrac{3}{4}\right|=1\)
làm hộ mik 3 con này cái
Cho \(x,y,z\ne0\) và x - y - z = 0. Tính \(B=\left(1-\dfrac{z}{x}\right)\left(1-\dfrac{x}{y}\right)\left(1+\dfrac{y}{z}\right)\)
Tìm \(x\)
1. \(\dfrac{1}{7}=\dfrac{8}{-x}\)
2. \(\dfrac{3x}{9}=\dfrac{2}{6}\)
3. \(4\dfrac{2}{5}:\left(\dfrac{-33}{10}\right)+x=-1\dfrac{5}{6}\)
4. \(45\%.x-2\dfrac{3}{8}=-1\dfrac{31}{40}\)
5. \(\left(x-2\dfrac{1}{4}\right):\left(-\dfrac{5}{6}\right)=3\)
a, \(\dfrac{1}{x^2-x}+\dfrac{2x}{4x^3}-\dfrac{1}{x^2+x}+1\)
\(b,\dfrac{1}{x^2-x+1}+1-\dfrac{x^2+2}{x^3+1}\)
\(c,\dfrac{1}{x\left(x-y\right)\left(x-z\right)}+\dfrac{1}{y\left(y-z\right)\left(y-x\right)}+\dfrac{1}{z\left(z-x\right)\left(z-y\right)}\)
khẩn cấp @Aki Tsuki @Nhã Doanh @Phùng Khánh Linh @DƯƠNG PHAN KHÁNH DƯƠNG... @Nguyễn Thanh Hằng hlep me T.T
tìm các số nguyên x,y,z biết \(\dfrac{-24}{-6}\)=\(\dfrac{x}{3}\)= \(\dfrac{4}{y^2}\)= \(\dfrac{z^3}{-2}\)
Tìm x,y biết \(\dfrac{1-2y}{18}=\dfrac{1+4y}{24}=\dfrac{1+6y}{6x}\)
Tìm x,y,z biết \(\dfrac{x}{3}=\dfrac{y}{4}\) ; \(\dfrac{y}{5}=\dfrac{z}{7}\) và x+y+z =9^2
Tìm n để A= 12n^2 - 5n -25 là số nguyên tố