x2-xy+y+2=0
\(\Leftrightarrow\) x2-1-xy+y=-3
\(\Leftrightarrow\) (x-1)(x+1)-y(x-1)=-3\(\Leftrightarrow\) (x-1)(x-y+1)=-3
x,y \(\in z\) \(\Rightarrow\) x-1;x-y+1\(\in z\)
=>x-1;x-y+1\(\in U\left(-3\right)=\left\{3;-3;1;-1\right\}\)
\(\Rightarrow\) x,y\(\in\left\{4,6;-2,-2;2,6;0,-2\right\}\)