\(ab+2a-3b=11\)
\(\Rightarrow a\left(b+2\right)-3b-6=5\)
\(\Rightarrow a\left(b+2\right)-3\left(b+2\right)=5\)
\(\Rightarrow\left(a-3\right)\left(b+2\right)=5\)
Ta có bảng sau:
a - 3 | 1 | -1 | 5 | -5 |
b + 2 | 5 | -5 | 1 | -1 |
a | 4 | 2 | 8 | -2 |
b | 3 | -7 | -1 | -3 |
Vậy cặp số \(\left(a;b\right)\) là \(\left(4;3\right);\left(2;-7\right);\left(8;-1\right);\left(-2;-3\right)\)