Question

Tìm a , b , c , d \(\in\) N biết:

\(\frac{30}{43}\) = \(\frac{1}{a+\frac{1}{b+\frac{1}{c+\frac{1}{d}}}}\)

Giups mk với nhé! Ai làm xong trước 9h15 sáng nay mk tick hết nha!!!

Answer 1

Có: \(\frac{30}{43}=\frac{1}{\frac{43}{30}}=\frac{1}{1+\frac{13}{30}}=\frac{1}{1+\frac{1}{2+\frac{4}{13}}}=\frac{1}{1+\frac{1}{2+\frac{1}{3+\frac{1}{4}}}}\)

=>a=1; b=2 ; c=3 ; d=4

Answer 2

\(\frac{30}{43}=\frac{1}{\frac{43}{30}}\)

     \(=\frac{1}{1+\frac{1}{\frac{30}{13}}}=\frac{1}{1+\frac{1}{2+\frac{4}{13}}}\)

     \(=\frac{1}{1+\frac{1}{2+\frac{1}{\frac{13}{4}}}}=\frac{1}{1+\frac{1}{2+\frac{1}{3+\frac{1}{4}}}}\)

Vậy a = 1 ; b = 2 ; c = 3 ; d = 4