\(2x\left(-2x+1\right)-2x^2=2\\ \Leftrightarrow-4x^2+2x-2x^2=2\\ \Leftrightarrow-6x^2+2x-2=0\\ \Leftrightarrow x\in\varnothing\left(-6x^2+2x-2=-6\left(x^2-2\cdot\dfrac{1}{6}x+\dfrac{1}{36}+\dfrac{11}{36}\right)=-6\left(x-\dfrac{1}{6}\right)^2-\dfrac{11}{6}< 0\right)\)
bài tập 1: tìm x, biết
a) (x - 3)(x + 3) = (x - 2)2 - 1
b) (2x - 1)2 = (2x +5)(2x - 5) + 2
c) (x + 1)3 = x2(x - 2) + 5(x2 - 1
d) (x2 - 3x + 9)(x + 3) = (x - 2)3 + (3x - 1)(2x + 3)
tính giá trị biểu thức a) (2x+3).(2x-3)-(2x+1)2 tại x=1/2 b) (x-2)2 - (x-1).(x+1)-x.(1-x) tai x=5 c) (2x-1)2 + (x+1)2 +2.(2x-1).(x-1) tại x= -2 d) (2x-1)2 -2.(2x+3).(2x+5) +(2x+5)2 tại x=2022
(x + 2)2-2x-4 = 0
(2x+5)2-2(2x +1)(2x +5 ) + (2x + 1)2
tìm x 4.(x+1).(-x+2)+(2x-1).(2x+3)=-11 (2x+4).(3x+1).(x-2)-(-3x2 +1).(-2x+2/3)=-26/3
tìm x biết
1) \(\left(x+2\right)-\left(x^2-2x+4\right)-x\left(x^2+2\right)=15\)
2) \(\left(x+3\right)^3-x\left(3x+1\right)^2+\left(2x+1\right)\left(4x^2-2x+1\right)=28\)
Tìm x, biết :
a) (x+4)2-x2(x+12)=16
c) (x+3)3-x(3x+1)2+(2x+1)(4x2-2x+1)=28
d) (x-2)3-(x+5)(x2-5x+25)-6x2=11
giải phương trình (x^2+3x+3)^3 + ( x^2 -x-1)^3 +(-2x^2-2x-1)^3=1
coi (x^2+3x+3)^3 = a
coi ( x^2 -x-1)^3 = b
coi (-2x^2-2x-1)^3 = c
Tìm x
a)(2x-1)^3-(2x-1)^3=-8
b)x(x-2)(x+2)-3(2x-1)^2-2x-5=-6x(x+1) c)(x+1)^3-(x-1)^3-6(x-1)^2=-10Tìm x, biết:
a) 16x2-(4x-5)2=15 b) (2x+1)(1-2x)+(1-2x)2=18
c) (x-5)2-x(x-4)=9 d) (x-5)2+(x-4)(1-x)=0
