Question

thực hiện phép tính

128-[68+8(37-35) mũ 2]:4

Answer 1

128 - [68+8(37-35)²]:4

= 128- [68+8. 2²]:4

= 128 - [68+8.4]:4

= 128 - [68+32]:4

= 128 - 100 : 4

= 128 -  25

= 103

 

 

Answer 2

\(128-\left[68+8.\left(37-35\right)^2\right]:4\)

\(=128-\left[68+8.2^2\right]:4\)

\(=128-\left[68+8.4\right]:4\)

\(=128-\left[68+32\right]:4\)

\(=128-100:4\)

\(=128-25\)

\(=103\)