a) \(175-\left(-25\right)+62-\left(1200+62\right)\)
\(=\left(175+25\right)+\left(62-62\right)-1200\)
\(=200-1200\)
\(=-1000\)
b) \(\left(-25\right)\cdot8\cdot\left(-4\right)\cdot\left(-125\right)\cdot3\)
\(=3\left[\left(-25\right)\cdot\left(-4\right)\right]\left[\left(-125\right)\cdot8\right]\)
\(=3\cdot100\cdot\left(-1000\right)\)
\(=-300000\)
c) \(27\cdot\left(-17\right)+17\cdot\left(-73\right)\)
\(=27\cdot\left(-17\right)+73\cdot\left(-17\right)\)
\(=\left(-17\right)\cdot\left(27+73\right)\)
\(=\left(-17\right)\cdot100\)
\(=-1700\)
d) \(512\cdot\left(2-128\right)-128\cdot\left(-512\right)\)
\(=512\cdot\left(2-128\right)+128\cdot512\)
\(=512\left(2-128+128\right)\)
\(=512\cdot2\)
\(=1024\)
a, 175 + 25 + 62 + 1200 -62
= 200 + 1200 + ( 62 - 62 )
= 1400
mình chỉ đủ thời gian làm câu a
a) 175−(−25)+62−(1200+62)175−(−25)+62−(1200+62)
=(175+25)+(62−62)−1200=(175+25)+(62−62)−1200
=200−1200=200−1200
=−1000=−1000
b) (−25)⋅8⋅(−4)⋅(−125)⋅3(−25)⋅8⋅(−4)⋅(−125)⋅3
=3[(−25)⋅(−4)][(−125)⋅8]=3[(−25)⋅(−4)][(−125)⋅8]
=3⋅100⋅(−1000)=3⋅100⋅(−1000)
=−300000=−300000
c) 27⋅(−17)+17⋅(−73)27⋅(−17)+17⋅(−73)
=27⋅(−17)+73⋅(−17)=27⋅(−17)+73⋅(−17)
=(−17)⋅(27+73)=(−17)⋅(27+73)
=(−17)⋅100=(−17)⋅100
=−1700=−1700
d) 512⋅(2−128)−128⋅(−512)512⋅(2−128)−128⋅(−512)
=512⋅(2−128)+128⋅512=512⋅(2−128)+128⋅512
=512(2−128+128)=512(2−128+128)
=512⋅2=512⋅2
=1024
