\(a,\left(-14\right)\cdot\left(-125\right)\cdot\left(+3\right)\cdot\left(-8\right)\\ =\left[\left(-125\right)\cdot\left(-8\right)\right]\cdot\left[3\cdot\left(-14\right)\right]\\ =1000\cdot\left(-42\right)\\ =-42000\)
Xem lại đề câu b nhé
\(D=2^{100}-2^{99}-2^{98}-...-2^2-2-1\\ =2^{100}-\left(2^{99}+2^{98}+...+2^2+2+1\right)\\ \text{Đặt }G=2^{99}+2^{98}+...+2^2+2+1\\ 2G=2^{100}+2^{99}+...+2^3+2^2+2\\ 2G-G=\left(2^{100}+2^{99}+...+2^3+2^2+2\right)-\left(2^{99}+2^{98}+...+2^2+2+1\right)\\ G=2^{100}-1\\ D=2^{100}-G\\ =2^{100}-\left(2^{100}-1\right)\\ =2^{100}-2^{100}+1\\ =1\)
b/(-25).34.2+/(-34).(-250)/
=(-50).34+34.250
=34.(-50+250)
=34.200
=6800
c/2D=2.(2100-299-...-22-2-1)
=2101-2100-...-23-22-2
2D-D=2101-2100-...-23-22-2-(2100-299-22-2-1)
D=2101-2.2100+1
D=2101-2101+1=1