Question

Thu gọn M= \(\left(2^1+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)

Giúp mình gấp với nhé!

Answer 1

\(M=1\left(2^1+1\right)\left(2^2+1\right)\left(2^4+1\right)...\left(2^{16}+1\right)=\left(2^1-1\right)\left(2^1+1\right)\left(2^2+1\right).....\left(2^{16}+1\right)=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)...\left(2^{16}+1\right)=\left(2^4-1\right)\left(2^4+1\right)....\left(2^{16}+1\right)=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)=\left(2^{16}-1\right)\left(2^{16}+1\right)=2^{32}-1\)