Question

thu gọn đa thức sau rồi tìm bậc của chúng

(-6\(^{x^2}\)yz) . (-\(\dfrac{4}{3}\)\(^{X^2}\)y\(^{z^3}\))

Answer 1

\(( -6x^2yz ) . ( \dfrac{-4}{3}x^2yz^3 )\)

\(= ( -6 . \dfrac{-4}{3} ) . ( x^2 . x^2 ) . ( y.y ) . ( z.z^3 )\)

\(= 8x^4y^2z^4\)

Bậc : \(4 + 4 + 2=10\)

 

Answer 2

\(=8x^4y^2z^4\)

Bậc : 10

Answer 3

\(\left(-6x^2yz\right).\left(-\dfrac{4}{3}x^2yz^3\right)\)

\(=\left(-6.-\dfrac{4}{3}\right)\left(x^2.x^2\right)\left(y.y\right)\left(z.z^3\right)\)

\(=8x^4y^2z^4\)

\(\text{Bậc là:10}\)