\(\left(\sqrt{x}+2\right)^2=16\\ \left(\sqrt{x}+2\right)^2=\left(\pm4\right)^2\\ \Rightarrow\left\{{}\begin{matrix}\left(\sqrt{x}+2\right)=4\\\left(\sqrt{x}+2\right)=-4\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}\sqrt{x}=6\\\sqrt{x}=2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=36\\x=4\end{matrix}\right.\)
Ko bít có đúng k nha! Làm bừa