\(\sqrt{3^2+4^2-\sqrt{1^3+2^3+3^3}}\)
=\(\sqrt{9+16-\sqrt{1+8+27}}\)
=\(\sqrt{25-\sqrt{36}}\)
=\(\sqrt{25-6}\)
=\(\sqrt{19}\)
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Bài 11: Số vô tỉ. Khái niệm về căn bậc hai
Các câu hỏi tương tự
bài 1: tính
a) 3/4+(-5/2)+(-3/5)
b) \(\sqrt{\left(7\right)^2}+\sqrt{\dfrac{25}{16}-\dfrac{3}{2}}\)
c)\(\dfrac{1}{2}.\sqrt{100}-\sqrt{\dfrac{1}{16}+\left(\dfrac{1}{3}\right)^0}\)
giúp mình với
1, tính
a, 7timessqrt{dfrac{6^2}{7^2}}-sqrt{25}+sqrt{dfrac{left(-3right)^2}{2}}
b, -sqrt{dfrac{64}{49}}-dfrac{3}{5}timessqrt{dfrac{25}{64}}+sqrt{0,25}
c, sqrt{dfrac{10000}{5}}-dfrac{1}{4}.sqrt{dfrac{16}{9}}+sqrt{dfrac{left(-3right)^2}{left(4right)}}
d, left|dfrac{1}{4}-sqrt{0,0144}right|-dfrac{3}{2}+sqrt{dfrac{81}{169}}
Đọc tiếp
giúp mình với
1, tính
a, \(7\times\sqrt{\dfrac{6^2}{7^2}}-\sqrt{25}+\sqrt{\dfrac{\left(-3\right)^2}{2}}\)
b, \(-\sqrt{\dfrac{64}{49}}-\dfrac{3}{5}\times\sqrt{\dfrac{25}{64}}+\sqrt{0,25}\)
c, \(\sqrt{\dfrac{10000}{5}}-\dfrac{1}{4}.\sqrt{\dfrac{16}{9}}+\sqrt{\dfrac{\left(-3\right)^2}{\left(4\right)}}\)
d, \(\left|\dfrac{1}{4}-\sqrt{0,0144}\right|-\dfrac{3}{2}+\sqrt{\dfrac{81}{169}}\)
Thực hiện phép tính
\(M=\left(18\dfrac{1}{3}:\sqrt{225}+8\dfrac{2}{3}.\sqrt{\dfrac{49}{4}}\right):\left[\left(12\dfrac{1}{3}+8\dfrac{6}{7}\right)-\dfrac{\left(\sqrt{7}\right)^2}{\left(3\sqrt{2}\right)^2}\right]:\dfrac{1704}{445}\)
tính \(\sqrt{\left(3-\sqrt{5}\right)^2}\)
\(\sqrt{\left(\sqrt{3-\sqrt{4}}\right)^2}\)
\(\sqrt{\left(7-\sqrt{34}\right)^2}\) giúp mik nha
Tìm x biết :
\(3x\sqrt{x+1}=40\)
\(\sqrt{x+1}+2=0\)
\(\sqrt{\left(x+1\right)^2}=3\)
\(\sqrt{x-3}=4\)
Tính:
B=[-\(\sqrt{2,25}\)+4\(\sqrt{\left(-2,15\right)^2}\)-(3\(\sqrt{\dfrac{7}{6}}\))2].\(\sqrt{1\dfrac{9}{16}}\)
C=\(3\dfrac{1}{2}\).\(\dfrac{4}{49}\)-[2,(4).\(2\dfrac{5}{11}\)]:(\(\dfrac{-42}{5}\))
1. Tìm x, biết : sqrt{x^2}0
2. Tính :
Aleft(0,75-0,6+dfrac{3}{7}+dfrac{3}{13}right).left(dfrac{11}{7}+dfrac{11}{3}+2,75-2,2right)
Bdfrac{left(1+2+3+...+100right)left(dfrac{1}{2}-dfrac{1}{3}-dfrac{1}{7}-dfrac{1}{9}right)left(63.1,2-21.3,6right)}{1-2+3-4+...+99-100}
Cleft|dfrac{4}{9}-left(dfrac{sqrt{2}}{2}right)^2right|+left|0,4+dfrac{dfrac{1}{3}-dfrac{2}{5}-dfrac{3}{7}}{dfrac{2}{3}-dfrac{4}{5}-dfrac{6}{7}}right|
Help me !!! Nhanh lên nha chiều mk phải nộp rồi
Đọc tiếp
1. Tìm x, biết : \(\sqrt{x^2}=0\)
2. Tính :
\(A=\left(0,75-0,6+\dfrac{3}{7}+\dfrac{3}{13}\right).\)\(\left(\dfrac{11}{7}+\dfrac{11}{3}+2,75-2,2\right)\)
\(B=\dfrac{\left(1+2+3+...+100\right)\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{9}\right)\left(63.1,2-21.3,6\right)}{1-2+3-4+...+99-100}\)
\(C=\left|\dfrac{4}{9}-\left(\dfrac{\sqrt{2}}{2}\right)^2\right|+\left|0,4+\dfrac{\dfrac{1}{3}-\dfrac{2}{5}-\dfrac{3}{7}}{\dfrac{2}{3}-\dfrac{4}{5}-\dfrac{6}{7}}\right|\)
Help me !!! Nhanh lên nha chiều mk phải nộp rồi
So sánh :1. \(\sqrt{26+3}\)và \(\sqrt{63}\)
2.\(\frac{1}{2}\)và \(\sqrt{\frac{3-1}{2}}\)
Tìm x biết :a) \(\sqrt{x}\) = \(x\)
b) \(x-2\sqrt{x}=0\)
c) \(\sqrt{x+1}=1-x\)
d) \(\sqrt{3x^2+4}+\sqrt{2004x^2+1}=3-4x^2\)
e) \(\sqrt{3x^2+4}+\sqrt{2007x^2+25}=7-69x^2\)