Chương I - Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
Tính:a. 5sqrt{2}-2sqrt{48}+6sqrt{75}-sqrt{108}b.2sqrt{147}-dfrac{3}{32}sqrt{192}+dfrac{4}{18}sqrt{243}-dfrac{1}{10}sqrt{300}c. -dfrac{1}{2}sqrt{108}+dfrac{1}{15}sqrt{75}-dfrac{1}{22}sqrt{363}+sqrt{12} d. dfrac{5}{8}sqrt{48}-dfrac{1}{33}sqrt{363}+dfrac{3}{14}sqrt{147}-dfrac{1}{4}sqrt{192}e. dfrac{3}{2}sqrt{12}+dfrac{7}{5}sqrt{75}-dfrac{9}{10}sqrt{300}+dfrac{11}{6}sqrt{108}
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Tính:
a. \(5\sqrt{2}-2\sqrt{48}+6\sqrt{75}-\sqrt{108}\)
b.\(2\sqrt{147}-\dfrac{3}{32}\sqrt{192}+\dfrac{4}{18}\sqrt{243}-\dfrac{1}{10}\sqrt{300}\)
c. \(-\dfrac{1}{2}\sqrt{108}+\dfrac{1}{15}\sqrt{75}-\dfrac{1}{22}\sqrt{363}+\sqrt{12}\)
d. \(\dfrac{5}{8}\sqrt{48}-\dfrac{1}{33}\sqrt{363}+\dfrac{3}{14}\sqrt{147}-\dfrac{1}{4}\sqrt{192}\)
e. \(\dfrac{3}{2}\sqrt{12}+\dfrac{7}{5}\sqrt{75}-\dfrac{9}{10}\sqrt{300}+\dfrac{11}{6}\sqrt{108}\)
1, dfrac{6-sqrt{6}}{sqrt{6}-1}+dfrac{6+sqrt{6}}{sqrt{6}}
2, dfrac{6-6sqrt{3}}{1-sqrt{3}}+dfrac{3sqrt{3}+3}{sqrt{3}+1}
3, dfrac{3+sqrt{3}}{sqrt{3}}+dfrac{sqrt{6}-sqrt{3}}{1-sqrt{2}}
4, dfrac{sqrt{15}-sqrt{12}}{sqrt{5}-2}+dfrac{6+2sqrt{6}}{sqrt{3}+sqrt{2}}
5, left(dfrac{3sqrt{125}}{15}-dfrac{10-4sqrt{5}}{sqrt{5}-2}right)cdotdfrac{1}{sqrt{5}}
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1, \(\dfrac{6-\sqrt{6}}{\sqrt{6}-1}+\dfrac{6+\sqrt{6}}{\sqrt{6}}\)
2, \(\dfrac{6-6\sqrt{3}}{1-\sqrt{3}}+\dfrac{3\sqrt{3}+3}{\sqrt{3}+1}\)
3, \(\dfrac{3+\sqrt{3}}{\sqrt{3}}+\dfrac{\sqrt{6}-\sqrt{3}}{1-\sqrt{2}}\)
4, \(\dfrac{\sqrt{15}-\sqrt{12}}{\sqrt{5}-2}+\dfrac{6+2\sqrt{6}}{\sqrt{3}+\sqrt{2}}\)
5, \(\left(\dfrac{3\sqrt{125}}{15}-\dfrac{10-4\sqrt{5}}{\sqrt{5}-2}\right)\cdot\dfrac{1}{\sqrt{5}}\)
Tính:
\(A=3\sqrt{20}-\sqrt{45}+2\sqrt{18}+\sqrt{72}\)
\(B=\dfrac{12}{3-\sqrt{5}}-\dfrac{16}{\sqrt{5}+1}\)
\(C=10\sqrt{\dfrac{1}{5}}+\dfrac{1}{5}\sqrt{125}-2\sqrt{20}\)
\(E=\sqrt{\left(\sqrt{3}+1\right)^2}-\sqrt{\left(\sqrt{3}-2\right)^2}\)
\(F=\sqrt{6+2\sqrt{5}}-\sqrt{9-4\sqrt{5}}\)
Tính:
\(A=3\sqrt{20}-\sqrt{45}+2\sqrt{18}+\sqrt{72}\)
\(B=\dfrac{12}{3-\sqrt{5}}-\dfrac{16}{\sqrt{5}+1}\)
\(C=10\sqrt{\dfrac{1}{5}}+\dfrac{1}{5}\sqrt{125}-2\sqrt{20}\)
\(E=\sqrt{\left(\sqrt{3}+1\right)^2}-\sqrt{\left(\sqrt{3}-2\right)^2}\)
\(F=\sqrt{6+2\sqrt{5}}-\sqrt{9-4\sqrt{5}}\)
So sánh:
a) \(\dfrac{1}{4}\sqrt{8}\) và \(\dfrac{2}{3}\sqrt{12}\)
b) \(\dfrac{5}{2}\sqrt{\dfrac{1}{6}}\)và \(6\sqrt{\dfrac{1}{35}}\)
c) \(\dfrac{1}{6}\sqrt{18}\)và \(\dfrac{1}{2}\sqrt{2}\)
So sánh:
a) \(\dfrac{1}{4}.\sqrt{8}\)và \(\dfrac{2}{3}.\sqrt{12}\)
b) \(\dfrac{5}{2}.\sqrt{\dfrac{1}{6}}\)và \(6.\sqrt{\dfrac{1}{35}}\)
c) \(\dfrac{1}{6}.\sqrt{18}\)và \(\dfrac{1}{2}.\sqrt{2}\)
17 tháng 6 2023 lúc 14:39
Cho hai biểu thức:
A = \(\dfrac{24}{\sqrt{x}+6}\) và B = \(\dfrac{\sqrt{x}}{\sqrt{x}+6}+\dfrac{1}{\sqrt{x}-6}+\dfrac{17\sqrt{x}+30}{x-36}\) với \(x\ge0;x\ne36\)
c) Biểu thức B sau khi thu gọn được B = \(\dfrac{\sqrt{x}+6}{\sqrt{x}-6}\). Tìm các giá trị của x để AB \(\le12\)
Thực hiện phép tính
-left(5+2sqrt{6}right)left(49-20sqrt{6}right)sqrt{5-2sqrt{6}}
- dfrac{1}{sqrt{2}+sqrt{2+sqrt{3}}}+dfrac{1}{sqrt{2}-sqrt{2-sqrt{3}}}
-dfrac{left(5+sqrt{2}right)^2-8sqrt{5}}{2sqrt{5}-4}
- sqrt{14-8sqrt{3}}-sqrt{24-12sqrt{3}}
- dfrac{sqrt{3}}{1-sqrt{sqrt{3}+1}}+dfrac{sqrt{3}}{1+sqrt{sqrt{3}+1}}
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Thực hiện phép tính
-\(\left(5+2\sqrt{6}\right)\left(49-20\sqrt{6}\right)\sqrt{5-2\sqrt{6}}\)
- \(\dfrac{1}{\sqrt{2}+\sqrt{2+\sqrt{3}}}+\dfrac{1}{\sqrt{2}-\sqrt{2-\sqrt{3}}}\)
-\(\dfrac{\left(5+\sqrt{2}\right)^2-8\sqrt{5}}{2\sqrt{5}-4}\)
- \(\sqrt{14-8\sqrt{3}}-\sqrt{24-12\sqrt{3}}\)
- \(\dfrac{\sqrt{3}}{1-\sqrt{\sqrt{3}+1}}+\dfrac{\sqrt{3}}{1+\sqrt{\sqrt{3}+1}}\)
Rút gọn
a) 2sqrt{5}-sqrt{125}-sqrt{80}+sqrt{605}
b) dfrac{10+2sqrt{10}}{sqrt{5}+sqrt{2}}+dfrac{8}{1-sqrt{5}}
c) sqrt{15-sqrt{216}}+sqrt{33-12sqrt{6}}
d) dfrac{2sqrt{8}-sqrt{12}}{sqrt{18}-sqrt{48}}-dfrac{sqrt{5}+sqrt{27}}{sqrt{30}+sqrt{162}}
e) 2sqrt{dfrac{16}{3}}-3sqrt{dfrac{1}{27}}-6sqrt{dfrac{4}{75}}
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Rút gọn
a) \(2\sqrt{5}-\sqrt{125}-\sqrt{80}+\sqrt{605}\)
b) \(\dfrac{10+2\sqrt{10}}{\sqrt{5}+\sqrt{2}}+\dfrac{8}{1-\sqrt{5}}\)
c) \(\sqrt{15-\sqrt{216}}+\sqrt{33-12\sqrt{6}}\)
d) \(\dfrac{2\sqrt{8}-\sqrt{12}}{\sqrt{18}-\sqrt{48}}-\dfrac{\sqrt{5}+\sqrt{27}}{\sqrt{30}+\sqrt{162}}\)
e) \(2\sqrt{\dfrac{16}{3}}-3\sqrt{\dfrac{1}{27}}-6\sqrt{\dfrac{4}{75}}\)