Question

so sánh không cần tính A=100² với B= 102.98

 

 

 

 

 

 

 

 

 

Answer 1

Ta có:

\(A=100^2=\left(98+2\right).100=98.100+200\)

\(B=98.102=98.\left(100+2\right)=98.100+196\)

Vì \(98.100+200>98.100+196\) nên \(A>B\)

Vậy A > B

Answer 2

\(A=100^2\)

\(B=102\cdot98=\left(100+2\right)\left(100-2\right)=100^2-4\)

=> \(A>B\)

Answer 3

Ta có:
\(102\cdot98=\left(100+2\right)\left(100-2\right)=100^2-4< 100^2\)

Vậy A > B

 

Answer 4

A = 100²

B = 102 . 98 = ( 100 +2) . (102 - 2) = 100² - 4 

100² > 100² - 4 => A > B