Ta có \(P_1>0,P_2< 0,P_3=0\) (Vì có thừa số \(\dfrac{0}{11}=0\))
Do đó \(P_2< P_3< P_1\)
Ta có P11 > 0, P2 < 0, P3 = 0 (vì có thừa số 0/11 = 0)
Do đó P2 < P3 < P1.
So sánh các tích sau bằng cách hợp lí
P1=\(\left(-\dfrac{57}{95}\right).\left(-\dfrac{29}{60}\right)\) ; P2= \(\left(-\dfrac{5}{11}\right).\left(-\dfrac{49}{73}\right)\left(-\dfrac{6}{23}\right)\)
P3= \(\dfrac{-4}{11}.\dfrac{-3}{11}.\dfrac{-2}{11}.........\dfrac{3}{11}.\dfrac{4}{11}\)
Tính bằng cách hợp lí :
\(\left(\dfrac{4}{9}-\dfrac{5}{11}\right):\dfrac{3}{10}+\left(\dfrac{3}{9}-\dfrac{9}{11}\right):\dfrac{3}{10}-\left(\dfrac{2}{9}-\dfrac{8}{11}\right).\left(\dfrac{-10}{3}\right)\)
Các bn giúp mik vs mai mik nộp bài r
a)\(\dfrac{\dfrac{2}{3}-}{\dfrac{8}{3}-}\dfrac{\dfrac{2}{5}+}{\dfrac{8}{5}+}\dfrac{\dfrac{2}{7}-}{\dfrac{8}{7}-}\dfrac{\dfrac{2}{9}+}{\dfrac{8}{9}+}\dfrac{\dfrac{2}{11}}{\dfrac{8}{11}}\)
b)\(\left(\dfrac{1}{2}-1\right)\left(\dfrac{1}{3}-1\right)\left(\dfrac{1}{4}-1\right)...\left(\dfrac{1}{50}-1\right)\left(\dfrac{1}{51}-1\right)\)
thực hiện phép tính:
a,\(\left(\dfrac{2}{3}\right)^3-\left(\dfrac{3}{4}\right)^2.\left(-1\right)^5\)
b,\(12:\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)
c,\(\dfrac{7}{22}:\dfrac{3}{11}+\dfrac{7}{22}:\dfrac{4}{11}\)
d,\(\dfrac{12}{35}.\left(\dfrac{7}{4}+\dfrac{13}{4}\right)-\dfrac{1}{3}\)
Giúp mk với
Tinh:
\(\dfrac{-3}{5}.51\dfrac{11}{13}+\dfrac{3}{5}.21\dfrac{11}{13}\)
\(\left|\dfrac{-3}{4}\right|.\left|-\dfrac{2}{3}\right|\)
\(\dfrac{-3}{5}+5\dfrac{1}{13}-\dfrac{2}{3}+1\dfrac{3}{5}-\dfrac{11}{33}\)
\(\dfrac{3}{4}.\sqrt{16}-10.\sqrt{0,81}\)
\(\left(\dfrac{3}{4}\right)^3:\left(-\dfrac{3}{8}\right)^3\)
\(\dfrac{6^4.15^3}{8.9^3.10^3}\)
GIUP MK T ^ T
Tính :
a) \(-\dfrac{3}{4}.31\dfrac{11}{23}-0.75.8\dfrac{12}{23}\)
b) \(\left(2\dfrac{1}{3}+3\dfrac{1}{2}\right):\left(-4\dfrac{1}{6}+3\dfrac{1}{7}\right)+7\dfrac{1}{2}\)
c) \(4\dfrac{5}{9}:\left(\dfrac{-5}{7}\right)+5\dfrac{4}{9}:\left(\dfrac{-5}{7}\right)\)
d) \(4\dfrac{25}{16}+25\left(\dfrac{9}{16}:\dfrac{125}{64}:\dfrac{-27}{8}\right)\)
e) \(\dfrac{2}{3}-4\left(\dfrac{1}{2}+\dfrac{3}{4}\right)\)
Tinh
a) \(\left(-1,25\right).14,7.\left(-8\right)\)
b)\(\dfrac{3}{4}-1\dfrac{1}{6}\)
c)\(\dfrac{-3}{5}.51\dfrac{11}{13}+\dfrac{3}{5}.21\dfrac{11}{13}\)
d)\(\left|\dfrac{-3}{4}\right|.\left|-\dfrac{2}{3}\right|\)
e)\(\dfrac{-3}{5}+5\dfrac{1}{13}-\dfrac{2}{3}+1\dfrac{3}{5}-\dfrac{11}{33}\)
f)\(\dfrac{3}{4}.\sqrt{16}-10.\sqrt{0,81}\)
g)\(\left(\dfrac{3}{4}\right)^3:\left(-\dfrac{3}{8}\right)^3\)
h)\(\dfrac{6^4.15^3}{8.9^3.10^3}\)
GIUP MK T ^ T
Tính :
a) \(\left(\dfrac{-2}{3}+\dfrac{3}{7}\right):\dfrac{4}{5}+\left(\dfrac{-1}{3}+\dfrac{4}{7}\right):\dfrac{4}{5}\)
b) \(\dfrac{5}{9}:\left(\dfrac{1}{11}-\dfrac{5}{22}\right)+\dfrac{5}{9}:\left(\dfrac{1}{15}-\dfrac{2}{3}\right).\)
Tính:
a) \(\dfrac{-3}{4}.\dfrac{12}{-5}.\left(-\dfrac{25}{6}\right);\) b) \(\left(-2\right).\dfrac{-38}{21}.\dfrac{-7}{4}.\left(-\dfrac{3}{8}\right);\)
c) \(\left(\dfrac{11}{12}:\dfrac{33}{16}\right).\dfrac{3}{5};\) d) \(\dfrac{7}{23}.\left[\left(-\dfrac{8}{6}\right)-\dfrac{45}{18}\right].\)
