Question

so sánh

(a-b)^2 và (b-a)^2

Answer 1

\(\left(a-b\right)^2=a^2-2ab+b^2\)

\(\left(b-a\right)^2=b^2-2ab+a^2=a^2-2ab+b^2\)

Ta thấy: \(a^2-2ab+b^2=a^2-2ab+b^2\Rightarrow\left(a-b\right)^2=\left(b-a\right)^2\)

Answer 2

Ta có :

\(\left(a-b\right)^2=a^2-2ab+b^2\left(1\right)\)

\(\left(b-a\right)^2=b^2-2ab+a^2\left(2\right)\)

Từ ( 1 ) ; ( 2 )

\(\Rightarrow\left(a-b\right)^2=\left(b-a\right)^2\)

Vậy \(\left(a-b\right)^2=\left(b-a\right)^2\)