Ta có:
\(3^{22}=\left(3^2\right)^{11}=9^{11}\)
\(2^{33}=\left(2^3\right)^{11}=8^{11}\)
Vì \(9^{11}>8^{11}\) nên \(3^{22}>2^{33}\)
Vậy \(3^{22}>2^{33}\)
Ta có:
\(3^{22}=\left(3^2\right)^{11}=9^{11}\)
\(2^{33}=\left(2^3\right)^{11}=8^{11}\)
Vì \(9^{11}>8^{11}\) nên \(3^{22}>2^{33}\)
Vậy \(3^{22}>2^{33}\)
so sánh 3^22 và 2^33
So sanh
a,\(\frac{-1274}{2530}\)va 1,2
b,2515 va 810 .330
So sanh : \(\sqrt{2016}-\sqrt{2015}va\sqrt{\sqrt{2015}-}\sqrt{2014}\)
cho a , b thuoc Z , b > 0 . So Sanh hai so huu ti a/b va a+2001/b+2001
giup mik nha cac ban mik ko hieu
So sanh 2 phan so sau khong quy dong...
\(\frac{5}{-12}\) va \(\frac{-6}{17}\)
So sanh A va B :
A = \(\dfrac{-13}{21}\) Va B = \(\dfrac{9}{-14}\)
b ) A = \(\dfrac{99}{101}\) va B = \(\dfrac{2011}{2013}\)
c ) A= \(\dfrac{15^{11}+4
}{15^{11}+2}\) Va B = \(\dfrac{15^{21}+4}{15^{21}+2}\)
giúp mình với :(
may mem giai gjum mk
so sanh 2so huu ti
x=\(\dfrac{-5}{4}\) va y=\(-1\dfrac{1}{4}\)
1)Tìm x biết :/ x+\(\frac{1}{3}\)-4=-1
Bai naycac ban giai giup minh voi
2)tinh (\(\frac{2}{25}\)-1,008):\(\frac{4}{7}\):(\(\frac{13}{4}\)-\(6\frac{5}{9}\))*\(\frac{36}{17}\)
3)so sanh: \(\sqrt{21}\)+\(\sqrt{8}\)va 3+\(\sqrt{3}\)
So sanh khong quy dong:
\(\dfrac{5}{-12}\) va \(\dfrac{-6}{17}\)
Help me now!!!