\(1,\left(23\right)=1+23.0,\left(01\right)=1+23.\frac{1}{99}\\=1+\frac{23}{99}=\frac{99}{99}+\frac{23}{99}=\frac{122}{99}\)
đặt y=1,(23) => 100y=123,(23) =>99y=123,(23)-1,(23)
=>99y=122 =>y=122/99
Vậy 1,(23)=122/99
\(1,\left(23\right)=1+23.0,\left(01\right)=1+23.\frac{1}{99}=1+\frac{23}{99}=\frac{99}{99}+\frac{23}{99}=\frac{122}{99}\)
1,(23)=1+\(\frac{23}{99}\) = \(\frac{122}{99}\)