\(\dfrac{3.17.11}{22.9}=\dfrac{17}{6}\)
\(\dfrac{84.45}{49.54}=\dfrac{10}{7}\)
\(\dfrac{4.7.22}{33.14}=\dfrac{4}{3}\)
\(\dfrac{3\cdot7\cdot11}{22\cdot9}=\dfrac{1\cdot7\cdot1}{2\cdot3}=\dfrac{7}{6}\\ \dfrac{84\cdot45}{49\cdot54}=\dfrac{12\cdot5}{7\cdot6}=\dfrac{10}{7}\\ \dfrac{4\cdot7\cdot22}{33\cdot14}=\dfrac{4\cdot1\cdot2}{3\cdot2}=\dfrac{4}{3}\)
a) Ta có: \(\dfrac{3\cdot7\cdot11}{22\cdot9}\)
\(=\dfrac{3\cdot7\cdot11}{11\cdot2\cdot3\cdot3}\)
\(=\dfrac{7}{6}\)
b) Ta có: \(\dfrac{84\cdot45}{49\cdot54}\)
\(=\dfrac{7\cdot12\cdot9\cdot5}{7\cdot7\cdot6\cdot9}\)
\(=\dfrac{10}{7}\)
