a) Ta có: \(\dfrac{11\cdot4-11}{2-13}\)
\(=\dfrac{11\cdot\left(4-1\right)}{-11}\)
\(=\dfrac{33}{-11}=-3\)
b) Ta có: \(\dfrac{9\cdot6-9\cdot2}{18}\)
\(=\dfrac{9\cdot\left(6-2\right)}{18}\)
\(=\dfrac{36}{18}=2\)
c) Ta có: \(\dfrac{13\cdot2-13\cdot3}{1-14}\)
\(=13\cdot\dfrac{\left(2-3\right)}{-13}\)
=1