Question

Rút Gọn :

\(\dfrac{x\sqrt{x}+27}{\sqrt{x}+3}\)

Answer 1

Ta có:\(\dfrac{x\sqrt{x}+27}{\sqrt{x}+3}\)

\(=x-\sqrt{x}+9.\)

Answer 2

\(\dfrac{x\sqrt{x}+27}{\sqrt{x}+3}=\dfrac{\left(\sqrt{x}\right)^3+3^3}{\sqrt{x}+3}=\dfrac{\left(\sqrt{x}+3\right)\left[\left(\sqrt{x}\right)^2-3\sqrt{x}+9\right]}{\sqrt{x}+3}=x-3\sqrt{x}+9\)