Question

Rút gọn

\(B=\frac{x+2}{x+3}.\frac{x+3}{x+4}:\frac{x+4}{x+5}.\frac{\left(x+4\right)^2}{x+5}\)

Answer 1

Câu hỏi của Nguyễn Thành Đăng - Toán lớp 8 - Học toán với OnlineMath

Answer 2

\(B=\dfrac{x+2}{x+3}.\dfrac{x+3}{x+4}\div\dfrac{x+4}{x+5}.\dfrac{\left(x+4\right)^2}{x+5}\)

\(B=\dfrac{x+2}{x+3}.\dfrac{x+3}{x+4}.\dfrac{x+5}{x+4}.\dfrac{\left(x+4\right)^2}{x+5}\)

\(B=\dfrac{\left(x+2\right)\left(x+3\right)\left(x+5\right)\left(x+4\right)^2}{\left(x+3\right)\left(x+4\right)\left(x+4\right)\left(x+5\right)}\)

\(B=\dfrac{\left(x+2\right)\left(x+3\right)\left(x+4\right)^2\left(x+5\right)}{\left(x+3\right)\left(x+4\right)^2\left(x+5\right)}\)

\(B=x+2\)