\(B=\dfrac{3+\sqrt{3}}{\sqrt{2+\sqrt{3}}}\)
\(\dfrac{B}{\sqrt{2}}=\dfrac{3+\sqrt{3}}{\sqrt{2}\left(\sqrt{2+\sqrt{3}}\right)}\)
\(=\dfrac{\sqrt{3}\left(\sqrt{3}+1\right)}{\sqrt{4+2\sqrt{3}}}\)
\(=\dfrac{\sqrt{3}\left(\sqrt{3}+1\right)}{\sqrt{\left(\sqrt{3}+1\right)^2}}\)
\(=\dfrac{\sqrt{3}\left(\sqrt{3}+1\right)}{\sqrt{3}+1}=\sqrt{3}\)
\(\Rightarrow B=\sqrt{3}.\sqrt{2}=\sqrt{6}\)