Ta có: \(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}\) = \(\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}\) = \(\frac{2^5.8}{2^5.22}\) = \(\frac{8}{22}\) =\(\frac{56}{154}\)
\(\frac{3^4.5-3^6}{3^4.13+3^4}\) = \(\frac{3^4.\left(5-3^2\right)}{3^4.\left(13+1\right)}\) = \(\frac{3^4.\left(-4\right)}{3^4.14}\) = \(\frac{-4}{14}\)= \(\frac{-44}{154}\)
Rút gọn rồi quy đồng mẫu các phân số sau :
a)\(\frac{5.6+5.7}{5.8+20}\)và\(\frac{8.9-4.15}{12.7-180}\)
b)\(\frac{-5-5.3^2}{5^3+5^2.3^2}\)và\(\frac{4^6.9^5+68.120}{8^4.3^{12}-6^{11}}\)
help
Rút gon rồi quy đồng mẫu các phân số
\(\frac{8.9-4.15}{12.7-180}\)
1,Tính tổng:a,\(\frac{2}{1.3}\)+\(\frac{2}{3.5}\)+\(\frac{2}{5.7}\)+....+\(\frac{2}{99.101}\)
b,\(\frac{5}{1.3}\)+\(\frac{5}{3.5}\)+\(\frac{5}{5.7}\)+....+\(\frac{5}{99.101}\)
\(\frac{2}{3.5}+\frac{3}{5.8}+\frac{11}{8.19}+\frac{13}{19.32}+\frac{25}{32.57}+\frac{30}{57.87}\)\(\frac{2}{3.5}+\frac{3}{5.8}+\frac{11}{8.19}+\frac{13}{19.32}+\frac{25}{32.57}+\frac{30}{57.87}\)
tính
B=\(\frac{\left(\frac{1}{2}\right)^{10}.5-\left(\frac{1}{4}\right)^5.3}{\frac{1}{1024}.\frac{1}{3}-\left(\frac{1}{2}\right)^{11}}\)
\(\frac{7256.4375-725}{3650+4375.7255}\)
\(\frac{3^{10}.11+3^{10}.5;}{3^9.2^4}\)\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)
\(\left(125^3.7^5-175^5.5\right):2001^{2002}\)
1. So sánh A và B:
\(A=\frac{4}{7}+5+\frac{3}{7^2}+\frac{5}{7^3}+\frac{6}{7^4}\); \(B=\frac{5}{7^3}+\frac{6}{7^2}+\frac{5}{7^4}+\frac{4}{7}+5\)
Quy đồng mẫu các phân số:\(\frac{-3}{44}\) ; \(\frac{-11}{18}\); \(\frac{5}{-36}\)
Nêu cách quy đồng mẫu số các phân số có số âm
bài 1 : thực hiện phép tính
1) \(\frac{2}{3}+\frac{3}{4}+\frac{-1}{6}\) 2) \(\frac{1}{2}-\frac{2}{5}+\frac{-7}{10}\)
