Question

phân tích:

(x²+x)²+4x²+4x-12

Answer 1

\(\left(x^2+x\right)^2+4x^2+4x-12=x^4+2x^3+x^3+4x^2+4x-12=3x^3+5x^2+4x-12\) \(3x^3-3x^2+8x^2-8x+12x-12=2x^2\left(x-1\right)+8x\left(x-1\right)+12\left(x-1\right)=\left(x-1\right)\left(2x^2+8x+12\right)\)

Answer 2

sorry thiếu dầu =

Answer 3

\(B=\left(x^2+x\right)^2+4x^2+4x-12\)

\(=\left(x^2+x\right)^2+4\left(x^2+x\right)-12\)

Đặt \(x^2+x=t\), ta có:

\(B=t^2+4t-12\)

\(=t^2+6t-2t-12\)

\(=t\left(t+6\right)-2\left(t+6\right)\)

\(=\left(t+6\right)\left(t-2\right)\)

\(=\left(x^2+x+6\right)\left(x^2+x-2\right)\)

Chúc bạn học tốt!