`a)3-2\sqrt{3}=(\sqrt{3})^2-2\sqrt{3}=\sqrt{3}(\sqrt{3}-2)`
`b)2\sqrt{3}-\sqrt{6}=\sqrt{6}.\sqrt{2}-\sqrt{6}=\sqrt{6}(\sqrt{2}-1)`
`a, 3 - 2 sqrt 3 = (sqrt 3)^2 - 2 sqrt 3 = sqrt 3 . (sqrt 3 - 2)`
`b, `2 sqrt 3 - sqrt 6 = sqrt 12 - sqrt 6 = sqrt 6. sqrt 2 - sqrt 6 = sqrt 6(sqrt 2 - 1)`
\(a)3-2\sqrt{3}\\=3-2\sqrt{3}.1+1\\=(\sqrt{3}-1)^2\\b)2\sqrt{3}-\sqrt{6}\\=2\sqrt{3}-\sqrt{2}\sqrt{3}\\=\sqrt{2}\sqrt{3}(\sqrt{2}-1)\\=\sqrt{6}(\sqrt{2}-1)\)
a)
3 - 2√3
= (√3)2 - 2√3
= √3(√3 - 2)
b)
2√3 - √6
= √6 . √2 - √6
= √6( √2 -1)