Question

Phân tích thành nhân tử

\(x^2-x+\frac{5}{36}\)

Answer 1

\(x^2-x+\frac{5}{36}\)

\(=x^2-\frac{1}{6}x-\frac{5}{6}x+\frac{5}{36}\)

\(=x\left(x-\frac{1}{6}\right)-\frac{5}{6}\left(x-\frac{1}{6}\right)\)

\(=\left(x-\frac{1}{6}\right)\left(x-\frac{5}{6}\right)\)

Answer 2

\(x^2-x+\frac{5}{36}\)

\(=x^2-\frac{1}{6}x-\frac{5}{6}x+\frac{5}{36}\)

\(=x\left(x-\frac{1}{6}\right)-\frac{5}{6}\left(x-\frac{1}{6}\right)\)

\(=\left(x-\frac{1}{6}\right)\left(x-\frac{5}{6}\right)\)

Answer 3

\(x^2-x+\frac{5}{36}\)
\(=x^2-\frac{1}{6}x-\frac{5}{6}x+\frac{5}{36}\)
\(=x\left(x-\frac{1}{6}\right)-\frac{5}{6}\left(x-\frac{1}{6}\right)\)
\(\left(x-\frac{1}{6}\right)\left(x-\frac{5}{6}\right)\)

Answer 4

x²-x+5/36

=x²-x+1/4-1/4+5/36

=(x-1/2)²-1/9

=> (x-1/2-1/9)(x-1/2+1/9)

=(x-11/18)(x-7/18)