Question

Phân tích thành nhân tử:

a, a⁴-b⁴

b,a⁶-b⁶

Answer 1

a) a^4 - b^4 = (a^2)^2 - (b^2)^2 = (a^2+b^2)(a^2-b^2) = (a^2+b^2)(a+b)(a-b)

Answer 2

a) a⁴ - b⁴ = (a²)² - (b²)²

= ( a² - b²) (a² + b²)

= ( a - b)(a + b)( a² + b²)

Answer 3

a) \(a^4-b^4\)

=\(\left(a^2\right)^2-\left(b^2\right)^2\)

=\(\left(a^2-b^2\right)\left(a^2+b^2\right)\)

=\(\left(a-b\right)\left(a+b\right)\left(a^2+b^2\right)\)

b) \(a^6-b^6\)

= \(\left(a^3\right)^2-\left(b^3\right)^2\)

=\(\left(a^3-b^3\right)\left(a^3+b^3\right)\)

=\(\left(a^3-3a^2b+3ab^2-b^3\right)\left(a^3+3a^2b+3ab^2+b^3\right)\)