Question

Phân tích đa thức thành nhân tử : x^5+x^4+x^3+x^2+x+1

MIK ĐANG CẦN GẤP

Answer 1

`x^5+x^4+x^3+x^2+x+1`

`=x^4(x+1)+x^2(x+1)+(x+1)`

`=(x+1)(x^4+x^2+1)`

 

Answer 2

\(=\left(x^5+x^4+x^3\right)+\left(x^2+x+1\right)\\ =x^3\left(x^2+x+1\right)+\left(x^2+x+1\right)\\ =\left(x^3+1\right)\left(x^2+x+1\right)\\ =\left(x+1\right)\left(x^2-x+1\right)\left(x^2+x+1\right)\\ =\left(x+1\right)\left[x^4-\left(x+1\right)^2\right]\)