x^4+x^2−6
=(x^2)^2−x^2−6
đặt x^2=a
a^2-a-6
=(a−3)(a+2)
=(x^2−3)(x^2+2)
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x4+x 2-6=x 4-2x2+ 3x2-6=x2(x2-2)+3(x2-2)=(x2-2)( x2-3)
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\(x^4+x^2-6\)
\(=\left(x^2\right)^2+2x^2.\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{4}-6\)
\(=\left(x^2+\dfrac{1}{2}\right)^2-\dfrac{25}{4}\)
\(=\left(x^2+\dfrac{1}{2}\right)^2-\left(\dfrac{5}{2}\right)^2\)
\(=\left(x^2+\dfrac{1}{2}-\dfrac{5}{2}\right)\left(x^2+\dfrac{1}{2}+\dfrac{5}{2}\right)\)
\(=\left(x^2-2\right)\left(x^2+3\right)\)
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