Câu hỏi của Bi Bi

Question

phân tích đa thức thành nhân tử

x4+2019x2+2018x+2019

Nguyễn Việt Lâm · Accepted Answer

$=x^4-x+2019x^2+2019x+2019$

$=x\left(x^3-1\right)+2019\left(x^2+x+1\right)$

$=x\left(x-1\right)\left(x^2+x+1\right)+2019\left(x^2+x+1\right)$

$=\left(x^2-x\right)\left(x^2+x+1\right)+2019\left(x^2+x+1\right)$

$=\left(x^2-x+2019\right)\left(x^2+x+1\right)$Câu trả lời: $=x^4-x+2019x^2+2019x+2019$

$=x\left(x^3-1\right)+2019\left(x^2+x+1\right)$

$=x\left(x-1\right)\left(x^2+x+1\right)+2019\left(x^2+x+1\right)$

$=\left(x^2-x\right)\left(x^2+x+1\right)+2019\left(x^2+x+1\right)$

$=\left(x^2-x+2019\right)\left(x^2+x+1\right)$

Nguyễn Thành Trương · Answer

$x^4+2019x^2+2018x+2019$

$=\left(x^4-x\right)+\left(2019x^2+2019x+2019\right)$

$=x\left(x^3-1\right)+2019\left(x^2+x+1\right)$

$=x\left(x-1\right)\left(x^2+x+1\right)+2019\left(x^2+x+1\right)$

$=\left(x^2+x+1\right)\left[x\left(x-1\right)+2019\right]$

$=\left(x^2+x+1\right)\left(x^2-x+2019\right)$Câu trả lời: $x^4+2019x^2+2018x+2019$

$=\left(x^4-x\right)+\left(2019x^2+2019x+2019\right)$

$=x\left(x^3-1\right)+2019\left(x^2+x+1\right)$

$=x\left(x-1\right)\left(x^2+x+1\right)+2019\left(x^2+x+1\right)$

$=\left(x^2+x+1\right)\left[x\left(x-1\right)+2019\right]$

$=\left(x^2+x+1\right)\left(x^2-x+2019\right)$

Nguyễn Huyền Trâm · Answer

x4+2019x2+2018x+2019

= x4−x+2019x2+2019x+2019=x4−x+2019x2+2019x+2019

=x(x3−1)+2019(x2+x+1)=x(x3−1)+2019(x2+x+1)

=x(x−1)(x2+x+1)+2019(x2+x+1)=x(x−1)(x2+x+1)+2019(x2+x+1)

=(x2−x)(x2+x+1)+2019(x2+x+1)=(x2−x)(x2+x+1)+2019(x2+x+1)

=(x2−x+2019)(x2+x+1)Câu trả lời: x4+2019x2+2018x+2019

= x4−x+2019x2+2019x+2019=x4−x+2019x2+2019x+2019

=x(x3−1)+2019(x2+x+1)=x(x3−1)+2019(x2+x+1)

=x(x−1)(x2+x+1)+2019(x2+x+1)=x(x−1)(x2+x+1)+2019(x2+x+1)

=(x2−x)(x2+x+1)+2019(x2+x+1)=(x2−x)(x2+x+1)+2019(x2+x+1)

=(x2−x+2019)(x2+x+1)

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