Question

phân tích đa thức thành nhân tử

x²y +xy+x+1

Answer 1

\(x^2y+xy+x+1\)

\(=\left(x^2y+xy\right)+\left(x+1\right)\)

\(=xy\left(x+1\right)+\left(x+1\right)\)

\(=\left(x+1\right)\left(xy+1\right)\)

Answer 2

\(x^2y+xy+x+1\)

\(=xy\left(x+1\right)+\left(x+1\right)\)

\(=\left(x+1\right)\left(xy+1\right)\)