Question

Phân tích đa thức thành nhân tử: (x^2+x)^2-2(x^2+x)-15

Answer 1

=(x^2+x)^2-2(x^2+x)+1-16

=(x^2+x-1)^2-4^2

=(x^2+x-1-4)(x^2+x-1+4)

=(x^2+x-5)(x^2+x+3)

Answer 2

\(\left(x^2+x\right)^2-2\left(x^2+x\right)-15\)

\(=\left(x^2+x\right)^2-2\left(x^2+x\right)+1-16\)

\(=\left(x^2+x+1\right)^2-4^2\)

\(=\left(x^2+x+1+4\right)\left(x^2+x+1-4\right)\)

\(=\left(x^2+x+5\right)\left(x^2+x-3\right)\)

Answer 3

Sorry , bạn nha : Sửa lại :

\(\left(x^2+x\right)^2-2\left(x^2+x\right)-15\)

\(=\left(x^2+x\right)^2-2\left(x^2+x\right)+1-16\)

\(=\left(x^2+x-1\right)^2-4^2\)

\(=\left(x^2+x-1+4\right)\left(x^2+x-1-4\right)\)

\(=\left(x^2+x+3\right)\left(x^2+x-5\right)\)