Question

Phân tích đa thức thành nhân tử

x²-y²+2y-1

Answer 1

Ta có:

\(x^2-y^2+2y-1=x^2-\left(y^2-2y+1\right)=x^2-\left(y-1\right)^2\)

\(=\left(x-y+1\right)\left(x+y-1\right)\)

Answer 2

\(x^2-y^2+2y-1\\ =x^2-\left(y^2-2y+1\right)\\ =x^2-\left(y-1\right)^2\\ =\left(x-y+1\right)\left(x+y-1\right)\)

Answer 3

=x²-(y²-2y+1)=x²-(y-1)²=(x-y+1)(x+y-1)