Question

phân tích đa thức sau

x\(^2\)+14x+48

x\(^2\)-9+4xy+y\(^2\)

Answer 1

a, \(x^2+14x+48\)

\(=x^2+14x+49-1\)

\(=\left(x+7\right)^2-1\)

\(=\left(x+6\right)\left(x+8\right)\)

Answer 2

\(x^2+14x+48=x^2+14x+49-1=\left(x+7\right)^2-\left(1\right)^2=\left(x+7+1\right)\left(x+7-1\right)=\left(x+8\right)\left(x+6\right)\)