Question

Phan tich cac da thuc thanh nhan tu:

x³- 2x² - x + 2

x² + 6x - y² + 9

Answer 1

x^3-2x^2-x+2=x^2(x-2)-(x-2)=(x^2-1)(x-2)=(x-1)(x+1)(x-2)

Answer 2

a)(x³- x) - (2x² - 2)

= x (x² - 1) - 2 (x² - 1)

= (x - 2) (x²-1)

Answer 3

a) \(x^3-2x^2-x+2=\left(x^3-x\right)+\left(-2x^2+2\right)\)

\(=x\left(x^2-1\right)-2\left(x^2-1\right)=\left(x-2\right)\left(x^2-1\right)=\left(x-2\right)\left(x+1\right)\left(x-1\right)\)

b) \(x^2+6x-y^2+9=\left(x^2+6x+9\right)-y^2\)

\(\left(x+3\right)^2-y^2=\left(x+3-y\right)\left(x+3+y\right)\)