Theo mk thì cứ thay vào r ghpt
Vì \(M\left(1;5\right)\in\left(P\right)\)
Thay x=1;y=5
\(a+b+2=5\Leftrightarrow a+b=3\)
tương tự
\(4a-2b+2=8\Leftrightarrow4a-2b=6\)
\(\Rightarrow\left\{{}\begin{matrix}a+b=3\\4a-2b=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=2\\b=1\end{matrix}\right.\)
\(\Rightarrow a+2b=2+2=4\)