Question

ohaan tích đa thức sau thành nhân tữ 4x^4+36x^2+81-36x^2

Answer 1

\(4x^4+36x^2+81-36x^2=\left(4x^4+36x^2+81\right)-36x^2=\left(2x^2+9\right)^2-36x^2=\left(2x^2+9+6x\right)\left(2x^2+9-6x\right)\)

Answer 2

\(4x^4+36x^2+81-36x^2\)

\(=\left(2x-9\right)^2-\left(6x\right)^2=\left(2x^2+9+6x\right)\left(2x^2-6x+9\right)=\left(2x^2+6x+9\right)\left(2x^2-6x+9\right)\)

Answer 3

\(4x^4+36x^2+81-36x^2=\left(2x^2\right)^2+9^2=\left(2x^2\right)^2+36x^2+9^2-\left(6x\right)^2=\left(2x^2+9\right)^2-\left(6x\right)^2=\left(2x^2-6x+9\right)\left(2x^2+6x+9\right)\)