CaCO3 --to--➢ CaO + CO2
\(n_{CaCO_3}=\dfrac{120}{100}=1,2\left(mol\right)\)
Theo PT: \(n_{CaO}=n_{CaCO_3}=1,2\left(mol\right)\)
\(\Rightarrow m_{CaO}=1,2\times56=67,2\left(kg\right)< 71,6kg\)
⇒ Chất rắn thu được sau phản ứng gồm: CaCO3 dư và CaO
\(m_{CO_2}=120-71,6=48,4\left(kg\right)\)
\(\Rightarrow n_{CO_2}=\dfrac{48,4}{44}=1,1\left(mol\right)\)
Theo PT: \(n_{CaCO_3}pư=n_{CO_2}=1,1\left(mol\right)\)
\(\Rightarrow m_{CaCO_3}pư=1,1\times100=110\left(kg\right)\)
\(\Rightarrow m_{CaCO_3}dư=120-110=10\left(kg\right)\)
\(\Rightarrow m_{CaO}=71,6-10=61,6\left(kg\right)\)
\(\Rightarrow\%CaCO_3dư=\dfrac{10}{71,6}\times100\%=13,97\%\)
\(\%CaO=\dfrac{61,6}{71,6}\times100\%=86,03\%\)
