\(CuCl_2+H_2S\rightarrow CuS+2HCl\)
\(m_{dd_{CuCl2}}=3,38.50=169\left(g\right)\)
\(n_{CuCl2}=\frac{169.20\%}{135}=0,25\left(mol\right)\)
\(n_{H2S}=\frac{50.20,4\%}{34}=0,3\left(mol\right)\)
Suy ra H2S dư
\(n_{CuS}=n_{CuCl2}=0,25\left(mol\right)\)
\(n_{HCl}=0,25.2=0,5\left(mol\right)\)
\(m_{dd_{Spu}}=169+50-0,25.96=195\left(g\right)\)
\(C\%_{HCl}=\frac{0,5.36,5}{195}.100\%=9,36\%\)