\(v_{tb}=\dfrac{s}{\dfrac{\dfrac{1}{2}s}{v'}+\dfrac{\dfrac{1}{2}s}{v''}}=\dfrac{s}{\dfrac{s}{20}+\dfrac{s}{15}}=\dfrac{s}{\dfrac{7s}{60}}=\dfrac{60}{7}\approx8,6\left(\dfrac{km}{h}\right)\)
Thời gian xe đi nửa quãng đường đầu:
\(t_1=\dfrac{S_1}{v_1}=\dfrac{\dfrac{S}{2}}{v_1}=\dfrac{S}{2v_1}=\dfrac{S}{2\cdot20}=\dfrac{S}{40}\left(h\right)\)
Thời gian xe đi trên nửa quãng đường sau:
\(t_2=\dfrac{S_2}{v_2}=\dfrac{\dfrac{S}{2}}{v_2}=\dfrac{S}{2v_2}=\dfrac{S}{2\cdot15}=\dfrac{S}{30}\left(h\right)\)
Vận tốc trung bình trên cả quãng đường:
\(v_{tb}=\dfrac{S_1+S_2}{t_1+t_2}=\dfrac{S}{\dfrac{S}{40}+\dfrac{S}{30}}=\dfrac{S}{\dfrac{7S}{120}}=\dfrac{120}{7}\approx17,14\)km/h