Ta có: \(v^2-v_0^2=2aS\Rightarrow v=\sqrt{2.24000.0,7}=40\sqrt{21}\left(m/s\right)\)
\(W_đ=\dfrac{1}{2}mv^2=\dfrac{1}{2}.0,03.\left(40\sqrt{21}\right)^2=504\left(J\right)\)
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