\(n_{H2}=\frac{1,12}{22,4}=0,05\left(mol\right)\)
Gọi \(\left\{{}\begin{matrix}n_{Zn}:a\left(mol\right)\\n_{ZnO}:b\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow65a+81b=4,06\left(g\right)\)
\(PTHH:Zn+2HCl\rightarrow ZnCl_2+H_2\)
________0,05__0,1_____0,05________ (mol)
\(ZnO+2HCl\rightarrow ZnCl_2+H_2O\)
b_______2b _________
\(\Rightarrow n_{Zn}=a=0,05\left(mol\right)\)
\(\Rightarrow\%m_{Zn}=\frac{0,05.65}{4,06}.100\%=80,05\%\)
\(\Rightarrow\%m_{ZnO}=100\%-80,05\%=19,95\%\)
b) \(b=0,01\left(mol\right)\)
\(n_{HCl}=0,1+2.0,01=0,12\left(mol\right)\)
\(\Rightarrow V_{dd\left(HCl\right)}=\frac{0,12}{2}=0,06\left(l\right)\)
